An antifreeze solution is prepared from 222.6 of ethylene glycol

Calculation of molality of the solution. Mass of ethylene glycol = 222.6 g Molar mass of ethylene glycol = `2xx12+6xx1+2xx16=62h mol^(-1)` `"Mass of solution (m)" = (" Mass of ethylene glycol / Molar mass")/(" Mass of solvent in kg")` = `=((222.6g)//(62 g mol^(-1)))/(0.2 kg)=17.95 mol kg^(-1)=17.95 m` Calculatrion of molarity of the solution. Total mass of solution = Mass of solute + Mass of solvent =222.6 + 200 422.6 g Density of solution= 1.072 g `mol^(-1)` `"Volume of solutin" = (" Mass of solution")/("Density of solution")=((422.6 g))/((1.072 g mol^(-1)))=394.2 mL` =0.3942 L. `"Molarity of solution (M)"=("Mass of ethylene glycon/Molar mass")/("Volume of solution in litres")` `=((22.6g)//(62 g mol^(-1)))/((0.3942 L))=9.10 mol L^(-1)=9.10 M`

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:2.8 An antifreeze solution is prepared from 222.6 g of ethylene glycol (C,H.02) and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072 g ml-', then what shall be the molarity of the solution?

An antifreeze solution is prepared from $222.6 \mathrm$, then what shall be the molarity of the solution? Step 1/3 Step 1: Calculate the moles of ethylene glycol and water in the solution. The molar mass of ethylene glycol (C2H6O2) is (2 × 12.01) + (6 × 1.01) + (2 × 16.00) = 62.07 g/mol. Moles of ethylene glycol = (222.6 g) / (62.07 g/mol) = 3.585 mol The molar mass of water (H2O) is (2 × 1.01) + (1 × 16.00) = 18.02 g/mol. Moles of water = (200 g) / (18.02 g/mol) = 11.098 mol Hi in this problem and interviewed solutions prepared consisting of 222 g of Italians like goal that is presented by a here And 200 g of water that is presented by B here. That in the city of the solution has given us 1.072 grand. But later we need to find out the morality of the solution as well as the minority of the solution. No modernity of solution is given by the formula number of moles of solute which is represented as a here divided by the weight of solvent that as a prison. Just be here in…