An ore on treatment with dilute hydrochloric acid

An ore on treatment with dilute hydrochloric acid produces brisk effervescence. Name the type of ore with one example. What steps will be required to obtain metal from the enriched ore? Also write the chemical equations for the reactions involved in the process. • Expert Answer *SolutionGPT is trained through our 100K subject matter experts using GPT-4

Hint- In order to solve the problem and find out the type of ore first we will see the gas that may have been produced. Then on the basis of gas produced we will see the type of ore and also the chemical reactions involved if any. Complete answer: As we know that brisk effervescence means $C\left( g \right)\] Hence, the given ore is a carbonate ore. Note- Calcination process is when the metal carbonates on treatment with the dilute hydrochloric acid, it releases carbon dioxide as a colorless and odorless gas with brisk effervescence. By the calcination process the metal carbonate ore is converted to their metal oxides. The common varieties of carbonate ore are calcite, dolomite and aragonite are prominent constituents of certain rocks: calcite is the principal mineral of limestone and marbles; dolomite occurs as a replacement for calcite in limestone.

(a) An ore on treatment with dilute hydrochloric acid produces brisk effervesces. What type of ore is this? What steps will be required to obtain metal from the enriched ore. , (b) Copper coin is kept immersed in silver nitrate solution for some time. What change will take place in coin and colour of the solution ? Write balanced chemical equation of the reaction involved. (a) Carbonate ore: (i) Calcination: Carbonate ore is heated in limited supply of air and oxide is obtained, e.g. (ii) Reduction with carbon: Oxide ore is heated with carbon ZnO (s) + C (s)→ Zn (s) + CO (g) (b) Copper, being more reactive than silver will displace silver from silver nitrate solution and there will be deposition of silver on copper coin. The colour of solution will turn to blue. Cu (s) + 2AgNO 3 (aq) → Cu(NO 3) 2 (aq) + 2Ag (s)