Volume occupied by one molecule of water

First, convert the volume of water → mass of water → moles of water → molecules of water. #1.0" g H"_2"O" × (1"cm"^3)/(1.00"g H"_2"O") × (1"mol H"_2"O")/(18.02"g H"_2"O") × (6.022 ×10^23"molecules")/(1"mol H"_2"O") =# #3.342 × 10^22" molecules"# Then calculate the volume of one molecule. Volume = #(1"cm"^3)/(3.342 × 10^22"molecules")# = 2.99 × 10⁻²³ cm³/molecule

Solution: (c) 1 m o l e = 6.023 × 1 0 23 m o l ec u l e 18 g = 6.02 × 1 0 23 m o l ec u l e 18 g = mass of 6.02 × 1 0 23 water molecules Mass of one water molecule = 6.023 × 1 0 23 18 ​ g Density = 1 g c m − 3 V o l u m e = De n s i t y M a ss o f o n e w a t er m o l ec u l e ​ = 6.023 × 1 0 23 × 1 18 ​ = c m 3 ≃ 3.0 x 1 0 − 23 c m 3

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Hint: Density relates mass and volume of the molecule. If we know any two of the quantities out of these two, we can find the third unknown quantity. Molecular weight of water is 18\[gmmo\].